In the above transformer the primary winding has N1 windings

In the above transformer, the primary winding has N1 windings and each half of the secondary winding has N2 windings. The turn ratio of the transformer (N1/N2) has given as N1/N2 11. Each diode\'s cut-n voltage is given as 0.6 V. The desiredvo output voltage has given to us as 8 volts. Detemine what should be the rms value at the primaryinput rms). Mark the choice that corresponds to your answer. 60

Solution

Vo=8 V =2*Vm/pi assuming Vo given is average voltage

Vm is peak of output voltage

Vm=8*pi/2=12.57 V (peak)

Transformer secondary peak voltage is V₂p=2(Vm+0.6)=26.34 V (peak)

V₂(RMS)=V₂p/sqrt(2)=26.34/1.414=18.625 V(RMS)

Primary RMS Voltage

V₁=V₂*N₁/N₂=18.625*11=204.88 V (RMS)

The above answer is not given in options

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Now assuming Vo=8 V RMS value=Vm/sqrt(2)

Vm is peak of output voltage

Vm=8*sqrt(2)=11.31 V (peak)

Transformer secondary peak voltage is V₂p=2(Vm+0.6)=23.83 V (peak)

V₂(RMS)=V₂p/sqrt(2)=23.83/1.414=16.85 V(RMS)

Primary RMS Voltage

V₁=V₂*N₁/N₂=16.85*11=185.33 V (RMS)

this option is also no there and there is no more possibilities