Given a standard normal distribution determine the following
Solution
A)
Using a table/technology, the left tailed area of this is
P(z < 1.4 ) = 0.9192 [ANSWER]
*****************
b)
P(z>1.4) = 1 - P(z<1.4) = 1-0.9192 = 0.0808 [ANSWER]
********************
c)
P(z<-1.4) = P(z>1.4)
by symmetry. Thus,
p(z<-1.4) = 0.0808 [ANSWER]
********************
d)
z1 = lower z score = -0.5
z2 = upper z score = 1
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.3085
P(z < z2) = 0.8413
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.5328 [ANSWER]
***********************
e)
z1 = lower z score = 0.5
z2 = upper z score = 1.5
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.6915
P(z < z2) = 0.9332
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.2417 [ANSWER]
