A new scrub technique is being issued for the operating room
A new scrub technique is being issued for the operating rooms at kindred hospital prior to issuing the new technique they measured the contamination levels of the surgeons with their previous scrub technique, they then measured it again later with the new technique. The following contamination levels were reported for the 4 hospital surgeons.
At a significance level of .05, can we conclude that the contamination measurements are lower with the new scrub technique?
What is the null hypothesis?
What is the alternative hypothesis?
What test statistic should you use?
What is the calculated value of the test statistic?
What is the critical value of the test statistic?
What is the decision to fail or reject which hypothesis?
Interpret your results...
| Surgeons | ||||
| A | B | C | D | |
| Old Technoque | 6.6 | 9.0 | 11.2 | 6.3 |
| New Technique | 6.8 | 7.4 | 8.1 | 3.4 |
Solution
What is the null hypothesis?
there is no difference between Old Technoque and new Technoque
What is the alternative hypothesis?
there is difference between Old Technoque and new Technoque
What test statistic should you use?
t test
What is the calculated value of the test statistic?
t = 1.5724
What is the critical value of the test statistic?
The two-tailed P value equals 0.2565
What is the decision to fail or reject which hypothesis?
acept null hypothesis
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P value and statistical significance:
The two-tailed P value equals 0.2565
By conventional criteria, this difference is considered to be not statistically significant.
Confidence interval:
The mean of Group One minus Group Two equals 1.500
95% confidence interval of this difference: From -2.604 to 5.604
Intermediate values used in calculations:
t = 1.5724
df = 2
standard error of difference = 0.954
| Group | Group One | Group Two |
|---|---|---|
| Mean | 8.275 | 7.433 |
| SD | 2.294 | 0.651 |
| SEM | 1.147 | 0.376 |
| N | 4 | 3 |

