Sec 101 19 How many of the numbers from 10 through 83 have t
Sec. 10.1, #19
How many of the numbers from 10 through 83 have the sum of their digits equal to a perfect square?
There are ______ numbers whose digits sum to a perfect square.
Solution
The numbers starts form 10,11,12,....83.
10=1+0=1 which is a perfect square
1+3=4
2+2=4
3+1=4
4+0=4
thera are 4 numbers(13,22,31,40) whose sum is a perfect square.
1+8=9
2+7=9
3+6=9
4+5=9
5+4=9
6+3=9
7+2=9
8+1=9
9 is a perfect sq and there are 8 no in total whose sum=9 and it is a perfect square.
7+9=16
16 is a perfect sq and can be with 79 no only
There are 14 no in total whose digits sum to a perfect square.
.
