A maximum1 5 C maximum51 B minimum51 D minimum 15 Solve the

A) maximum;-1,- 5 C) maximum;-5,-1 B) minimum:-5,-1 D) minimum: (-1,-5 Solve the problem. 24) A developer wants to enclose a rectangular grassy lot that borders a city st per wants to enclose a rectangular grassy lot that borders a city street for parking. If 2 the developer has 236 feet of fencing and d largest area that can be enclosed? oes not fence the side along the street, what is the A) 13,924 ft2 B) 6962 ft2 C) 10,443 f2 D) 3481 ft2

Solution

let the length alon the street as l and width be b

we have 236 feet fencing for bordering and leaving one side along the street so

l+2b = 236

l = 236-2b

we know are of rectangle = l*b

now we will replace l= 236-2b

A = (236-2b)*(b)

A = 236b - 2b²

A\' = 236 -4b

so if the value needs to be maxiumum we need to derivate the quantity and equals to zero to find out at which it is maximum

236-4b = 0

b = 59

so ,

2b+l = 236

l = 236-2(59)

l = 118

so l= 118 , b = 59

now area A = l*b = 118*59 = 6962

therefore maxiumum area

A = 6962ft²