A battleship weighs 50000 tons Sea water has a specific grav

A battleship weighs 50000 tons. Sea water has a specific gravity of 1.03 , The bottom of the hull is 36 ft below the surface of water. What is the bottom of the hull? Assume that the sides of the hull are vertical and submerged part has constant area
A battleship weighs 50000 tons. Sea water has a specific gravity of 1.03 , The bottom of the hull is 36 ft below the surface of water. What is the bottom of the hull? Assume that the sides of the hull are vertical and submerged part has constant area

Solution

The depth of the bottom of the hull below the waterline determines the amount of weight on the ship (ship included.) because Archimidies principle works here. Hull is a watertight body, above which is the superstructure and deck of the ship. The surface line where the water meets the hull is called the water line. Desirably for less self weight a hull may be be built of wood in wooden ships and with fibreglass and steel or in composite of wood and foam to make it lighter.

Now given weight of ship = 50,000 tons =100000000 lbs

unit weight of water = 62.4 *1.03 = 64.272 lbs/ft3

Water depth = 36 ft,

So, if A is the surface area, then volume replaced = A*36 ft3

Now as per static equilibrium, corresponding water replaced must have a weight equal to that of ship weight, so

A*36*64.272 = 100000000

=> A = 43219.09 ft2 is the surface area of the ship.

A battleship weighs 50000 tons. Sea water has a specific gravity of 1.03 , The bottom of the hull is 36 ft below the surface of water. What is the bottom of the

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