Suppose that fabR and gabR are differentiable functions such
Suppose that f:(a,b)->R and g:(a,b)->R are differentiable functions such that f\'(x)=g\'(x) for all x an element of (a,b). Show that there exists a constant, C, such that f(x)=g(x)+c
Solution
Let, h=f(x)-g(x)
So, h\'(x)=0 for all x in (a,b)
INtegrating w.r.t. on (a,b) we get
h(x)=C , C is constant of integration
f(x)-g(x)=C
f(x)=C+g(x)
