Suppose that fabR and gabR are differentiable functions such

Suppose that f:(a,b)->R and g:(a,b)->R are differentiable functions such that f\'(x)=g\'(x) for all x an element of (a,b). Show that there exists a constant, C, such that f(x)=g(x)+c

Solution

Let, h=f(x)-g(x)

So, h\'(x)=0 for all x in (a,b)

INtegrating w.r.t. on (a,b) we get

h(x)=C , C is constant of integration

f(x)-g(x)=C

f(x)=C+g(x)

Suppose that f:(a,b)->R and g:(a,b)->R are differentiable functions such that f\'(x)=g\'(x) for all x an element of (a,b). Show that there exists a consta

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