A molecule has a dipole moment of magnitude 62001028 Cm The

A molecule has a dipole moment of magnitude 620.0*10^-28 C.m. The distance between the two charges is390.0*10^-14 m. Calculate the magnitude of the charges. If the molecule is place in electric field of magnitude of 15.0*10^3 N/C, what is the maximum torque on the diploe? [Note: maximum means theta = 90 degree.

Solution

the magnitude of the charges is,

     u = qL

     q = u / L

        = 62X10-28 / 390X10-14

        = 1.59X10^-15 C

the maximum torque is,

     torque = EqLsin90 = 15x10^3*1.59X10^-15 *390X10^-14 = 9.3e-23 N.m