Randomly arrange N couples on N tables each table has 2 peo
Randomly arrange N couples on N tables , each table has 2 people.
Let X = number of couples sitting together on a table. Find E(X). Solve it using indicator (0-1 type) random variable. Define your indicator random variable to get full credit. Otherwise, I will take out at least 2 points even if your answer is right.
You need a value for N to solve this proble. Assume N = 15
Solution
N coupres and N tables.
Can be arranged in N! ways as each couple has N choice, and ii couple N-1 choices, etc.
Now couple can sit in any of the two orders among themselfes
Hence total ways = 2(N!)
X = no of couples sitting to gether
X can take values from 0 to15 as N =15
There are two outcomes for a couple either sit together or not sit together.
All trials are independent.
p for a couple to gether
p = A husband or wife selects his spouse to sit near
= 1/699
q = 698/699
Hence Expected value = np = 15(1/699) = 15/699
