solve the following trigonometric equation sin2xsinx0 Give y

solve the following trigonometric equation sin^2(x)-sin(x)=0. Give your answers in exact radians where 0<=x<2pi

Solution

sin^2(x)-sin(x)=0. Give your answers in exact radians where 0<=x<2pi

sinx( sinx -1) =0

sinx =0 -----> x = 0, pi

sinx-1 =0

x= sin^-1(1) = pi/4 , pi-pi/4 = pi/4 , 3pi/4

Solution : x = 0, pi/4 , 3pi/4 , pi