Give the hypothesis statements calculations comparison value

Give the hypothesis statements, calculations, comparison values, and conclusions (including supporting reasons for conclusions).

Solution

NULL HYPOTHESIS: All the means of 3 types(Middle schools teachers, High school teacher, college teachers) are equal

ALTERNATIVE HYPOTHESIS: All the means of 3 types(Middle schools teachers, High school teacher, college teachers) are not equal

LEVEL OF SIGNIFICANCE: 5%

TEST STATISTIC:

We Use Anova One way (F test) to find the difference between several means

From the EXCEL

CONCLUSION:

F cal= 2.5165 and F critical value at 5% is=3.68

Hence F cal < F critical value, then we accept the null hypothesis.

ie., All the means of 3 types(Middle schools teachers, High school teacher, college teachers) are equal

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
Middle 6 192 32 119.2
High 6 235 39.16667 30.16667
College 6 261 43.5 91.9
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 404.7778 2 202.3889 2.516579 0.114173 3.68232
Within Groups 1206.333 15 80.42222
Total 1611.111 17
Give the hypothesis statements, calculations, comparison values, and conclusions (including supporting reasons for conclusions).SolutionNULL HYPOTHESIS: All the

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