You mate two mice with the following genotypes MmKkLlPpQqRr

You mate two mice with the following genotypes: MmKkLlPpQqRr x mmkkllppqqrr. Assume that each gene controls a different character and that the upper case allele is dominant, how many different genotypes and phenotypes do you expect?

Solution

Answer:

MmKkLlPpQqRr x mmkkllppqqrr

The number of types of gametes possible: 2^ n

Number of different kinds of gametes = 2 n , where n = number of heterozygous alleles (genes).

Gametes for MmKkLlPpQqRr= 2^ 6= 64 different kinds of gametes

Gametes for mmkkllppqqrr= 1 kind of gamete

how many different genotypes and phenotypes do you expect?

=64 x 1

64 different kinds