Consider two matrices a b compute the matrix product a b and

Consider two matrices a b compute the matrix product a b and the entered by product a. b

(a) given that matrix A,B.

find A*B,for multiplication of two matrices we take first row of first matrix and first colomn of second matrix.

A*B=matrix of [(0.-1 -1.0 1.3) (-1.0 0.-1 -1.0) (1.3 -1.0 0.-1)]

=[(0 0 3) (0 0 0) (3 0 0)] this is product of A*B

(B)given that C=((A-I)*(B+I))^-1

first we have to find the matrix C

A-I=[(0 -1 1) (-1 0 -1) (1 -1 0)]-[(1 0 0) (0 1 0) (0 0 1)] [HERE I=(1 0 0) (0 1 0) (0 0 1)]

=[(0-1 -1 0 1-0) (-1 -0 0-1 --1 -0) (1-0 -1 -0 0-1)]

A-I =[(-1 -1 1) (-1 -1 -1) (1 -1 -1)]

B+I=[(-1 0 3) (0 -1 0) (3 0 -1)]-[(1 0 0) (0 1 0) (0 0 1)]

=[(0 0 3) (0 0 0) (3 0 0)]

now C=((A-I)*(B+I)

=[(-1 -1 1) (-1 -1 -1) (1 -1 -1)]*[(0 0 3) (0 0 0) (3 0 0)]

=[{0 0 3) (0 0 0) (3 0 0)]

now find the inverse of C.

we have a formula for finding inverse of a matrix, c^-1=1/det(c)*(adj(C))

now find adj of C,it means transfose of matrix C.

C^T=[{0 0 3) (0 0 0) (3 0 0)]=adj(c)

now det(C)=[(0(0.0)-(0.0)+0(0.0)-(3.0)+3(0.0)-(3.0)]

=0+0+0

C^-1=I/det(C)*adj(c)

=1/0*[{0 0 3) (0 0 0) (3 0 0)]