Find the sum sigman 128 J 6n 6 2184 2492 2394 2268Solution

Find the sum. sigma_n = 1^28 J (6n - 6) 2184 2492 2394 2268

Solution

This can be written as

0+ 6+ 12+18+24+.......

We have to use the formula of sum of n terms of arithmetic series

which is

S_n=(n/2)(2a+(n-1)d)

Here n= 28, a= 0, d=6

S₂₈= 14(0+27(6))=2268

Correct answer is D