8 Problem 02059Apply a force triangle to the of equlibrium t

Problem 02.059-Apply a force triangle to the of equlibrium to a perticle -DEPENDENT MULTL PART PROBLEM- ASSIGN ALL PARTS Consider the figure in which -14. as shown 120b References Book& Resources Section Break Problem 02 059 . Apply force trwngle to the of e to o perticle DEPENDENT MULTHPART PROBLEM ASSIGN ALL PARTS Dimesity. 1000 points You did not rece ve full credit for this epa~tion ia previous mempt Reqdred omation Problem 02.059.a -Apply a force triangle to the of equilibrium to a particle Round the etermne the value a for which the tension in rope BC pait) mramum nal answer to the nearest Mole number You must ro dear we be re movin o to the nest The value or for which the tension in rope BCs minimum, is-ITT),

Solution

*rope only can handel tension

balence force in vertical direction

F_AC*Cos14 =1200 + F_CB *Sin   -------------------------1

balence force in horizontal directio

F_AC SIN14 = F_CB Cos

F_AC= F_CB Cos /SIN14

PUT this value in equ 1

F_CB Cos /SIN14*Cos14 =1200 + F_CB *Sin

F_CB*Cot 14*Cos = 1200+ F_CB *Sin

4.01078*F_CB *Cos - F_CB *Sin = 1200

F_CB (4.01078Cos - Sin) = 1200

F_CB = 1200 / (4.01078Cos - Sin)

TO MINIMISE F_CB (4.01078Cos - Sin) should be maximum

hence = 0^o

minimum tension in rope BC

PUT =0 in above expression

F_CB = 1200 / (4.01078Cos0 - Sin0) = 1200/4.01078 =299.2 lb = 299 lb