We selected a random sample of size 110 from a pool of unive

We selected a random sample of size 110 from a pool of university students and asked whether they use Facebook on a regular basis. Sixty replied yes. What would be your estimation of the standard error of the sample proportion of regular Facebook users based upon the given information?

0.002

0.047

0.064

0.247

Solution

Standard Error = Sqrt(p*(1-p)/n))
x = Mean
n = Sample Size,
Mean(x)=60
Sample Size(n)=110
Sample proportion =0.5455
Standard Error = Sqrt ( (0.5455*0.4545) /110) )
= 0.047