Homework SourseIs greater than the proportion earning less than 18 per hour
Is greater than the proportion earning less than $18 per hour
Is less than 50%
Is less than the proportion earning more than the mean wage
Is greater than the proportion earning less than $13 per hour
Cannot tell without knowing the standard deviation
| If the wages of workers for a given company are normally distributed with a mean of $15 per hour, then the proportion of the workers earning more than $13 per hour: |
Solution
Normal with Mean =15
proportion of workers earning more than 13 per hour
= 13-15/std dev = z
Z cannot be positive as std dev is positive and numerator is negative.
Hence z is negative
Thus prob for z negative is more than 50% definitely
Is greater than the proportion earning less than $13 per hour is the correct choice
