During an action potential Na ions move into the cell at a r
During an action potential, Na^+ ions move into the cell at a rate of about 3 times 10^-7mol/m^2s. How much power must be produced by the \"active Na^+ pumping\" system to produce this flow against a +30-mV potential difference? Assume that the axon is 40 cm long and 30 nm in diameter.
Solution
Curent
I =(3*10-7mol/m2-s)(6.02*10-23ions/mol)(1.602*10-19C/ion)*pi*0.4m*(30*10-6m)
I=1.09*10-6C/s
Power
P=VI =30*10-3*1.09*10-6
P=3.27*10-8 Watts
