Determine the maxcimum number of turning points of f fxx2x93
Determine the maxcimum number of turning points of f f(x)=-x2(x+9)3(x2-1)
Solution
f(x)=-x2(x+9)3(x2-1)
Any polynomial of degree n can have a minimum of zero turning points and a maximum of n1. However, this depends on the kind of turning point.
Sometimes, \"turning point\" is defined as \"local maximum or minimum only\". In this case:
here the degree of f(x) = 2+1+2=5
maximum number of turning points =5-1=4
