The melting point of each of 16 samples of a certain brand o
The melting point of each of 16 samples of a certain brand of hydrogenated vegetable oil was determined, resulting in a sample mean of 94.32. Assume that the distribution of melting point is normal with = 1.20.
If a level .01 test is used, what is (94), the probability of type II error when =94?
Solution
We first get the z score for the critical value. As z = (x - u) sqrt(n) / s, then as
x = critical value = 94.32
u = mean = 94
n = sample size = 16
s = standard deviation = 1.2
Thus,
z = (x - u) * sqrt(n) / s = 1.066666667
Thus, using a table/technology, the right tailed area of this is
P(z > 1.066666667 ) = 0.143061192 [ANSWER]
