State the appropriate null and alternate hypotheses the hy

-State the appropriate null and alternate hypotheses.

_______________

_______________

-the hypothesis test is a _____________tailed test.

-compute the p value. Round the answer to four decimal places. p value = _______________

-Determine whether to reject H0

-State a conclusion

Solution

Test For Significance of Difference Of Proportion
Null, No significance in proportion of residents with same wheezing in symtoms b/w bth Ho: p1 = p2
Alternate Hypothesis, There Is Significance between them H1: p1 != p2
Test Statistic
Sample 1 : X1 =58, n1 =370, P1= X1/n1=0.157
Sample 2 : X2 =30, n2 =173, P2= X2/n2=0.173
Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
P^=0.162
Q^ Value For Proportion= 1-P^=0.838
we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
Zo =(0.157-0.173)/Sqrt((0.162*0.838(1/370+1/173))
Zo =-0.491
| Zo | =0.491
Critical Value
The Value of |Z | at LOS 0.01% is 2.576
We got |Zo| =0.491 & | Z | =2.576
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -0.4907 ) = 0.6237
Hence Value of P0.01 < 0.6237,Here We Do not Reject Ho

No significance in proportion of residents with same wheezing in symtoms b/w bth

Ans)
Ho: p1 = p2, H1: p1 != p2
Z-test For Significance of Difference Of Proportion
Ha : ( P != -0.4907 ) = 0.6237
Do not Reject Ho
No significance in proportion of residents with same wheezing in symtoms b/w bth