Solve log2x 2 log4x 7 log16x Solve log2x 2 log4x 7 log

Solution

log₂(x) + 2 log₄(x) = 7 - log₁₆(x)

log₂(x) + 2 log_2²(x) = 7 - log_2⁴(x)

log_b^ca =(1/c)log_ba

log₂(x) + 2(1/2)log₂(x) = 7 - (1/4)log₂(x)

log₂(x) +log₂(x) = 7 - (1/4)log₂(x)

log₂(x) +log₂(x) + (1/4)log₂(x)= 7

(1+1+(1/4))log₂(x)= 7

(9/4)log₂(x)= 7

log₂(x)= 7*4/9

log₂(x)= 28/9

log_ab=c =>b=a^c

x= 2^28/9