A spaceship moves at speed 06c towards a source of light The

A spaceship moves at speed 0.6c towards a source of light. The speed of the light as measured by observers on the spaceship is greater than c less than c equal to c Nota Observer A in a train station sees a pendulum oscillating back and forth in a train that moves at speed 0.8c relative to the station. Observer A measures the period of the pendulum on the train to be T_A. Observer B is a passenger sitting on the train at rest next to the pendulum and measures the period of the pendulum to be T_B. Which of the following is true? T_A > T_B T_A T_B T_A

Solution

1. (c)- Equal to c -   since the speed of light doesnt depend on the velocity of frame of reference.

2. (b) - T_A<T_B      since person A frame is at rest and Person B frame is moving, relatively moving clocks will run slow to each other when measured from the frame one frame measuring the other

3. (a) TA > TB   is the same reason as above

4.(a) LA>LB , length in the rest frame A is greater when measured from the same length from a moving frame B.

5.(b) LA< LB , length when measure when it is moving is less than the original length.