Suppose two parents a father with the genotype AaBbCcDdee an

Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the genotype aabbCcDDEe, wanted to have children. Assume each locus follows Mendelian inheritance patterns for dominance. What proportion of the offspring will have each of the following characteristics? Round your answers to two decimal places.

UPU BIO K 322 Spring x C fi www.saplinglearning.com/ibiscms/mod/ibis/view.php?id 3176620 Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the genotype aabbCcDDEe, wanted to have children. Assume each locus follows Mendelian inheritance patterns for dominance What proportion of the offspring will have each of the following characteristics? Round your answers to two decimal places same genotype as the father e genotype as the mother Number Number 0.03 0.03 phenotypically resemble the father phenotypically resemble the mother Incorrect Number Number See lower panel for more information. 0.05 0.05 phenotypically resemble neither parent Number 0.9 3:18 PM O Ask me anything

Solution

AaBbCcDdee X aabbCcDDEe

Aa X aa = Aa, Aa, aa, aa, Therefore allele resembling father = ½ and of mother = ½

Bb X bb = Bb, Bb, bb, bb, Therefore allele resembling father = ½ and of mother = ½

Cc X Cc = Cc, Cc, cc, cc, Therefore allele resembling father = ½ and of mother = ½

Dd X DD = DD,DD,dD,dD, Therefore allele resembling father = ½ and of mother = ½

ee X Ee = eE,eE, ee,ee, Therefore allele resembling father = ½ and of mother = ½

JUST REMEMBER A POINT :

The probability of a heterozygote is 1/2 or 2/4

The probability of a homozygote is 1/4

Father :AaBbCcDdee =1/2x1/2x1/2x1/2x1/4= 1/64 = 0.015

Mother: aabbCcDDEe =1/4x1/4x1/2x1/4x1/4 = 1/512 = 0.0019

So 0.015 proportion of the offspring will have each of the following characteristics same genotype as father...

To match the given options..

Father should be

Father :AaBbCcddee =1/2x1/2x1/2x1x1/4= 1/32 = 0.03

Then option A is matching