Solve the following problems showing any necessary work This
Solve the following problems, showing any necessary work. This includes row operations. Find all ordered pairs (x, y) such that [x -1 2 y]^2 + [x y -2 1]^2 = -2 I_2 where I_2 is the 2 x 2 identity matrix, and A^2 = A. A.
Solution
( x 2 , -1 y)^2 = ( x^2-2 2x+2y , -x-y -2+y^2 )
(( x -2, 1 y )^2 = ( x^2 -2 -2x -2y , x +y -2 +y^2)
( x 2 , -1 y)^2 +(( x -2, 1 y )^2 = ( 2x^2 -4 0 , 0 -4+2y^2)
-2I = ( -2 0 , 0 -2 )
Now ( x 2 , -1 y)^2 +(( x -2, 1 y )^2 = ( -2 0 , 0 -2 )
( 2x^2 -4 0 , 0 -4+2y^2) = ( -2 0 , 0 -2 )
Equating the corresponding terms from LHS and RHS
we get \" 2x^2 -4 = -2 ----> 2x^2=2
x = + /- 1
Now -4 +2y^2 = -2
2y^2 =2
y = +/-1
Ordered Pairs ( x, y) ---> ( 1, 1) , ( -1, -1) , ( -1, 1) , and ( 1, -1)
![Solve the following problems, showing any necessary work. This includes row operations. Find all ordered pairs (x, y) such that [x -1 2 y]^2 + [x y -2 1]^2 = - Solve the following problems, showing any necessary work. This includes row operations. Find all ordered pairs (x, y) such that [x -1 2 y]^2 + [x y -2 1]^2 = -](/WebImages/20/solve-the-following-problems-showing-any-necessary-work-this-1044052-1761542828-0.webp)