Using the method of relative velocity determine the angular

Using the method of relative velocity, determine the angular velocity of member CD in Figure 1 Using the method of instantaneous centers, determine (a) angular velocity of ABC, (b) linear velocity of A, and (c) angular velocity of cylinder E.

Solution

solution:

1)velocity polygon is drawn as draw line in tangential direction to link ED along angle of 22.61 degree,the draw another line for velocity vector for CE at 126.84 degree and then draw line cutting this two line at angle of 53.13 degree and give velocity vector CD and from velocity analysis plot point along vector CE in opposite direction.

2)from close velocity polygon EDC,where length are

for conversion factor

1cm=5.368181 in/s

hence length are

CD=2.2 cm

CE=4.2 cm

ED=4.2 cm

4)in this we get velocity as

Vcd=11.81 in/s

Vec=4.2*5.368181=22.5463 in/s

Ved=4.2*5.368181=22.5463 in/s

5) for link CD we have

Vcd=Rcd*Wcd

from geometry we get

Rcd=7.6808 in

11.81=7.6808*Wcd

Wcd=1.5375 rad/s

5)for link ED

Ved=Red*Wed

Red=1.18 in

Wed=22.5463/1.18=19.1070 rad/s

7)velocity of linkage BC,as

Vc=22.5463 in/s

Vc devide in x and y direction,VCy produces moment around point B

Vbc=Rbc*Vcy

Vcy=Vc*sin53.13=18.03 in/s

Wabc=Vcy/Rbc=18.03/4.73=3.8133 rad/s

8) velocity at point A is

Va=Rba*Wabc=3.936*3.8133=15.0091 in/s