Find the equation of a qudratic function whose graph satisfi

Find the equation of a qudratic function whose graph satisfied the given conditions.

Vertex:(-4,12) y intercept:4

Quadratic equation in vertex for is given by

y= a(x-h)^2 +k

now given vertex (-4,12) i.e. h= -4 and k= 12, hence we have

y= a(x+4)^2 + 12

now y intercept is the point where x =0 hence

4= a(0+4)^2 +12

=> 4- 12 = 16a

=> -8 = 16a

=> a = -8/16 = -1/2

Therefore equation is

y= (-1/2) (x+4)^2 +12

=> (-1/2) (x^2 +8x+16) +12

=> y= (-1/2)x^2 - 4x +4