You observe the following numbers of individuals of each gen
You observe the following numbers of individuals of each genotype in a population:
AA Aa aa
250 800 200
a. What are the observed genotype frequencies in this population?
b. What are the allele frequencies in this populations?
c. What are the expected Hardy-Weinberg genotype frequencies?
d. What is the expected number of individuals of each genotype?
e. Is this population in H-W equilibrium? Do a chi-square to test
departure from H-W equilibrium and if there is a significant deviation from HW what could explain this?
Solution
a). The total number of individuals is = 1250
The frequency of AA is = 250/1250 = 0.2
The frequency of Aa is = 800/1250 = 0.64
The frequency of aa is = 200/1250 = 0.16
b). The frequency of dominant allele, A is = frequency of AA + ½ (frequency of Aa) = 0.2 + ½ (0.64) = 0.52
The frequency of recessive allele, a is = frequency of aa + ½ (frequency of Aa) = 0.16 + ½ (0.64) = 0.48
c). The expected Hardy-Weinberg genotype frequencies are,
The frequency of AA is = 0.52*0.52 = 0.2704
The frequency of Aa is = 2*0.52*0.48 = 0.4992
The frequency of aa is = 0.2304
d). The expected number of individuals with AA genotype is = 0.2704*1250 = 338
The expected number of individuals with Aa genotype is = 0.4992*1250 = 624
The expected number of individuals with aa genotype is = 0.2304*1250 = 288
