Find the inverse of x2x in Z3x32x2 Find the inverse of x2x i
Find the inverse of (x^2+x) in Z3/(x^3+2x+2).
Find the inverse of (x^2+x) in Z3/(x^3+2x+2).
Solution
[x^2 + x ] + [x^3 + 2x^2 + x + 2] = [x^3 + 3x^2 +2x + 2] = x^3 + 2x + 2
So thi sis the inverse
[x^3 + 2x^2 + x + 2]
![Find the inverse of (x^2+x) in Z3/(x^3+2x+2). Find the inverse of (x^2+x) in Z3/(x^3+2x+2).Solution[x^2 + x ] + [x^3 + 2x^2 + x + 2] = [x^3 + 3x^2 +2x + 2] = x Find the inverse of (x^2+x) in Z3/(x^3+2x+2). Find the inverse of (x^2+x) in Z3/(x^3+2x+2).Solution[x^2 + x ] + [x^3 + 2x^2 + x + 2] = [x^3 + 3x^2 +2x + 2] = x](/WebImages/20/find-the-inverse-of-x2x-in-z3x32x2-find-the-inverse-of-x2x-i-1044310-1761542997-0.webp)