Evaluate the integral of xydx over c minus 5x2ydy where the

Evaluate the integral of xydx over \'c\' minus 5x^2ydy where the curve C is represented by r(t)= ti + t^2j, for 0 < or = t < or = 1.

Solution

x=t, y=t^2

dx=dt, dy=2t dt



So the integral becomes

0..1t^3 dt-5t^4*2t dt=0..1 t^3-10t^5 dt

=t^4/4-10t^6/6|0..1=

=1/4-10/6=(6-40)/24=-34/24=-17/12

Evaluate the integral of xydx over \'c\' minus 5x^2ydy where the curve C is represented by r(t)= ti + t^2j, for 0 < or = t < or = 1.Solutionx=t, y=t^2 dx=

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