Evaluate the integral of xydx over c minus 5x2ydy where the
Evaluate the integral of xydx over \'c\' minus 5x^2ydy where the curve C is represented by r(t)= ti + t^2j, for 0  < or = t < or = 1.
Solution
x=t, y=t^2
 
 dx=dt, dy=2t dt
 
 So the integral becomes
0..1t^3 dt-5t^4*2t dt=0..1 t^3-10t^5 dt
=t^4/4-10t^6/6|0..1=
=1/4-10/6=(6-40)/24=-34/24=-17/12

