536 Calculate e the fineness modulus of aggregate A in Probl
Solution
(5.36) Solution:- Aggregate A
Seive size(mm) % passing % Retained Cumulative % retained
25 100 0 0
19 92 8 8
12.5 76 24 32
9.5 71 29 61
4.75 53 47 108
2.36 38 62 170
1.18 32 68 238
0.6 17 83 321
0.3 10 90 411
0.150 5 95 506
0.075 3 97 603
cumulative % retained =2458
Fineness modulus of aggregate A = cumulative % retained/100
= 2458/100
= 24.58
Maximum size of aggregate A is 19 mm
For 19 mm Aggregate , fineness modulus should be between 6 to 6.9
So Fineness modulus of aggregate A is not in range. So aggregate is not accepted.
Fineness modulus of aggregate A is maximum because small size aggregates are present in more quantity than large size aggregate
(5.27) (a) Answer
Maximum size of Aggregate A= 19 mm
Maximum size of Aggregate B = 12.5 mm
