Show that each equation is true for c 0 and c notequalto 1
Solution
a) logc48 - (logc3 + logc2) = logc8
Starting with left side
logc48 - (logc2 + logc3)
We have to use the following log rules
logab + logac=logabc
logab - logac = loga(b/c)
logc48 - logc(2*3)
= logc48 - logc6= logc(48/6)=logc8 that is equal to right side
b) 7logc4= 14 logc2
Starting with left side
7logc4
We have to use the following log rule
logabc= c logab
7logc22 = 7*2 logc2 = 14logc2 that is equal to right side
c)1/2(logc2 + logc6)= logc2 + logcsqrt3
Starting with left side
1/2(logc2 + logc6)
1/2(logc2 + logc(2*3))
1/2(logc2 + logc2 +logc3)
1/2(2logc2 + logc3) = logc2 + 1/2logc3 = logc2 + logcsqrt3 that is equal to right side
d) logc(5c)2 = 2(logc5 + 1)
Starting with the left side
logc(5c)2 = 2logc5c
= 2(logc5 + logcc)
and logcc=1
therefore logc(5c)2= 2(logc5 + 1) that is the right side
