exist Ay 10 Solutionlimx5Fx5 limx5Fx5 limx5Fxlimx5Fx so limx

exist Ay 10

Solution

limx->5-F(x)=5

limx->5+F(x)=5

limx->5-F(x)=limx->5+F(x)

so limx->5F(x)=5

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limx->-4-F(x)=5

limx->-4+F(x)=2

limx->-4-F(x)limx->-4+F(x)

so limx->-4F(x) doesnot exist

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limx->8-F(x)=2

limx->8+F(x)=2

limx->8-F(x)=limx->8+F(x)

so limx->8F(x)=2

 exist Ay 10 Solutionlimx->5-F(x)=5 limx->5+F(x)=5 limx->5-F(x)=limx->5+F(x) so limx->5F(x)=5 ---------------------------------------------------

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