exist Ay 10 Solutionlimx5Fx5 limx5Fx5 limx5Fxlimx5Fx so limx
exist Ay 10
Solution
limx->5-F(x)=5
limx->5+F(x)=5
limx->5-F(x)=limx->5+F(x)
so limx->5F(x)=5
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limx->-4-F(x)=5
limx->-4+F(x)=2
limx->-4-F(x)limx->-4+F(x)
so limx->-4F(x) doesnot exist
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limx->8-F(x)=2
limx->8+F(x)=2
limx->8-F(x)=limx->8+F(x)
so limx->8F(x)=2
