The quality control manager Ms Venkat at Mangal Light Ltd in
Solution
a)
 Note that              
               
 Lower Bound = X - z(alpha/2) * s / sqrt(n)              
 Upper Bound = X + z(alpha/2) * s / sqrt(n)              
               
 where              
 alpha/2 = (1 - confidence level)/2 =    0.025          
 X = sample mean =    350          
 z(alpha/2) = critical z for the confidence interval =    1.959963985          
 s = sample standard deviation =    100          
 n = sample size =    64          
               
 Thus,              
               
 Lower bound =    325.5004502          
 Upper bound =    374.4995498          
               
 Thus, the confidence interval is              
               
 (   325.5004502   ,   374.4995498   )[ANSWER]
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B)
No, as 400 is not within the confidence interval.
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c)
NO, as by central limit theorem, the distirbution of means will be approximately normally distirbuted regardless of the underlying distribution.
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