0 10 15 20 25 30 35 40 45 50 L 0 500 1000 1500 2000 2500 300

0 -10 -15 -20 -25 -30 -35 -40 -45 -50 L 0 500 1000 1500 2000 2500 3000 3500 4000 4500 5000 Frequency (Hz)

Solution

For chebyshev Type I filter for order N odd we will have (N+1)/2 pass band peaks for N is even we have N/2 passband peak and for N odd, odd number of passband peaks and vice versa.

Since there are 3 passband peaks which is odd, the order of filter would be odd.

(N+1)/2 = 3

N+1 = 6

N = 5; order of Chebyshev Type I filter