solution for Sullivan PRECALCULUS 10th edition chapter 14 qu

solution for Sullivan PRECALCULUS 10th edition chapter 1.4 question 38

2. 3) 38. Center (1.0) and containing the point (-3.2)

Solution

let a general point on circle be (x,y)

since (x,y),(-3,2) are points on the circle , their distances from centre(1,0) are equal

[(x-1)²+(y-0)²] =[(-3-1)²+(2-0)²]

[(x-1)²+y²] =[(-4)²+2²]

[(x-1)²+y²] =[16+4]

(x-1)²+y² =20

therefore equation of circle is (x-1)²+y² =20