In a random sample of 500 college students 23 say that they

In a random sample of 500 college students, 23% say that they read or watch the news every day. Develop a 90% confidence interval for the proportion of all students who read or watch the news on a daily basis.

Solution

The confidence interval is given below

0.375 – 0.1408 < P < 0.375 + 0.1408

=> 0.234 < P < 0.516

Therefore, 90% confidence interval estimates for the true proportion of current spring will be

0.234 < P < 0.516

Or, 23.4% < P < 51.6%

In a random sample of 500 college students, 23% say that they read or watch the news every day. Develop a 90% confidence interval for the proportion of all stud

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