61 In a routine clinical process observed times in minutes w

6.1 In a routine clinical process, observed times in minutes were 84, 76, 80, 84, and 76. One

observed employee was working 25 percent faster than the average worker. Allowance

factors for this job, based on the workday, add to 20 percent. What are the normal and

the standard times?

Solution

For the given data mean = 80 and std dev = 4

As one person is working 25% faster than average, we presume that the lowest one 76 may be the person who is doing fastest.

Let him convert 76 to std average as 76*1.25 = 95

Now adjusted data becomes 84,95,80,84 and 76

Adjustmenet for 20% allowance is 120% of 84,95...

= 100.8, 114, 96,100.8,91.2

Std times = average of 100.8, 114, 96,100.8,91.2

= 100.56

-------------------------------

Normal times = average of 84,95,80,84 and 76

=83.8

6.1 In a routine clinical process, observed times in minutes were 84, 76, 80, 84, and 76. One observed employee was working 25 percent faster than the average w

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