Solve log2x3 log2x2Solutionlog2x3 log2x2 3log2x log2x2 s

Solve:

log₂(x³) = (log₂(x))²

==> 3log₂(x) = (log₂(x))² since ln a^b = b lna

==> (log₂(x))² - 3log₂(x) = 0

==> log₂(x) [ log₂(x) - 3] = 0

==> log₂(x) = 0 , log₂(x) = 3

==> x = 2⁰ , x = 2³ since if log_b a = c ==> a = b^c

==> x = 1 , 8

Hence solution for given equation is x = 1 , x = 8