Solve the equation for solutions over the interval 02 pi by

Solve the equation for solutions over the interval [0.2 pi) by first solving for the trigonometric function. 8sinx +16= 16 Select the correct choice below and. if necessary, fill in the answer box to complete your choice The solution set is {}. (Type an exact answer, using a as needed Use a comma to separate answers as needed.) The solution is the empty set.

Solution

8sinx+16=16

8sinx=0

sinx=0

taking inverse on both sides

x=sin^-1(0)=0

And in region [0,360),solution is x=0,pi

therefore the solution is {0,pi}