1932 11612Solutionsolution abx bax using this relation we
     (1/9)^-3/2 - (1/16)^-1/2![(1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23  (1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23](/WebImages/20/1932-11612solutionsolution-abx-bax-using-this-relation-we-1045452-1761543719-0.webp) 
  
  Solution
solution-
(a/b)-x =( b/a)x
using this relation we get,
(1/9)-3/2-(1/16)-1/2
(9)3/2-(16)1/2
[(3)2]3/2-[(4)2]1/2
27-4
23
![(1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23  (1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23](/WebImages/20/1932-11612solutionsolution-abx-bax-using-this-relation-we-1045452-1761543719-0.webp)
solution-
(a/b)-x =( b/a)x
using this relation we get,
(1/9)-3/2-(1/16)-1/2
(9)3/2-(16)1/2
[(3)2]3/2-[(4)2]1/2
27-4
23
![(1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23  (1/9)^-3/2 - (1/16)^-1/2Solutionsolution- (a/b)-x =( b/a)x using this relation we get, (1/9)-3/2-(1/16)-1/2 (9)3/2-(16)1/2 [(3)2]3/2-[(4)2]1/2 27-4 23](/WebImages/20/1932-11612solutionsolution-abx-bax-using-this-relation-we-1045452-1761543719-0.webp)
