Find the exact value of the trigonometric function given tha

Find the exact value of the trigonometric function given that sin u = 3/5 and cos v = 5/13 . (Both u and v are in Quadrant II.) csc(u v)

sin u = 3/5 and cos v = 5/13 . (Both u and v are in Quadrant II.)

cosu = - 4/5 ; sinv = 12/13

csc(u v) = 1/sin(u -v)

sin( u -v) = sinucosv- sinv cosu

=(3/5)(-5/13) - (12/13)(-4/5)

= ( -15 +48)/65

= 33/65

csc( u -v) = 65/33