What number does each line of code print out Bridfly explain

What number does each line of code print out? Bridfly explain why.

printf(\"%d\ \", ( 0x40000000 << 1) >> 20);

printf(\"%d\ \", ( 0x40000000u << 1) >>20);

Solution

#include <stdio.h>

int main()
{
printf(\"%d\ \",0x40000000);
//Left shift 1 multiplies the number by 2. Result : 2147483648. Max value of int is 2147483647.
//Overflow changes sign to -2147483648.
printf(\"%d\ \",(0x40000000 << 1));
//Right shift by 1 divides the number by 2^1. So right shift by 20 will divide -2147483648 by 2^20. Result: -2048
printf(\"%d\ \", ( 0x40000000 << 1) >> 20);
  
//Below result will print 2048 because appending u at the end of constant makes it unsigned int. So sign will be ignored for this case.
printf(\"%d\ \", ( 0x40000000u << 1) >>20);
return 0;
}