Question2 1 pts Consider the following three code fragments
     Question2 1 pts Consider the following three code fragments: //Code Fragment 1: for (int elev = 0; elev ![Question2 1 pts Consider the following three code fragments: //Code Fragment 1: for (int elev = 0; elev Solutioncorrect sequence is [3,2,1] Code fragment 3: --  Question2 1 pts Consider the following three code fragments: //Code Fragment 1: for (int elev = 0; elev Solutioncorrect sequence is [3,2,1] Code fragment 3: --](/WebImages/20/question2-1-pts-consider-the-following-three-code-fragments-1045702-1761543873-0.webp) 
  
  Solution
correct sequence is [3,2,1]
Code fragment 3:
 -------------------
 It nneds to allocate small 24 chunks and inside it will allocate 16000 chunks.
 So mainly, the outer loop which contains less number of iterations will take less space.
So for
 code 3 -> 24
 code 2 --> 200
 code 1 -> 16000
So best to worst is 3,2,1
![Question2 1 pts Consider the following three code fragments: //Code Fragment 1: for (int elev = 0; elev Solutioncorrect sequence is [3,2,1] Code fragment 3: --  Question2 1 pts Consider the following three code fragments: //Code Fragment 1: for (int elev = 0; elev Solutioncorrect sequence is [3,2,1] Code fragment 3: --](/WebImages/20/question2-1-pts-consider-the-following-three-code-fragments-1045702-1761543873-0.webp)
