Fine polar coordinates of the point whose rectangular coordi

Fine! polar coordinates of the point whose rectangular coordinates are (2 squareroot 3, -2). (4, pi/6) (-4, - pi/6) (-4, 5 pi/6) (4, 7 pi/6)

Solution

(2sqrt3,-2)

R²=x²+y²

R²= (2sqrt3)²+(-2)²

R²= 16

R=+-4

theta=tan^-1(y/x)

theta=tan^-1(-2/2sqrt3) = tan^-1(-1/sqrt3)= 5pi/6

polar coordinate is (R,theta) = (-4, 5pi/6)

Hence the correct option is C