show that fA subset of fB does not always mean A is a subset
show that f(A) subset of f(B) does not always mean A is a subset of B.
Solution
show that f(A) subset of f(B) does not always mean A is a subset of B.
sol:
for example : let f(x)=x2
let A={1,2,3}
let B={-1,-2,-3,-4}
but A is not sub set of B
and agian f(A)={1,4,,9,16}
so f(A) subset of f(B)
this is a counter example
