show that fA subset of fB does not always mean A is a subset

show that f(A) subset of f(B) does not always mean A is a subset of B.

Solution

show that f(A) subset of f(B) does not always mean A is a subset of B.

sol:

for example : let f(x)=x2

let A={1,2,3}

let B={-1,-2,-3,-4}

but A is not sub set of B

and agian f(A)={1,4,,9,16}

so f(A) subset of f(B)

this is a counter example

show that f(A) subset of f(B) does not always mean A is a subset of B.Solutionshow that f(A) subset of f(B) does not always mean A is a subset of B. sol: for ex

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