Blood type AB is found in only 3 of the populationSolutionme

Blood type AB is found in only 3% of the population

Solution

mean=n*p=205*0.03 =6.15

standard deviation =sqrt(n*p*(1-p)) =sqrt(205*0.03*0.97) =2.442437

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(a) 5 or more will have this blood type

P(X>=5) = P((X-mean)/s >(5-6.15)/2.442437)

=P(Z>-0.47) = 0.6808 (from standard normal table)

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(b) between 5 and 10 will have this blood type

P(5<X<10) = P((5-6.15)/2.442437<Z<(10-6.15)/2.442437)

=P(-0.47<Z<1.58) =0.6238 (from standard normal table)

Blood type AB is found in only 3% of the populationSolutionmean=n*p=205*0.03 =6.15 standard deviation =sqrt(n*p*(1-p)) =sqrt(205*0.03*0.97) =2.442437 ----------

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