Homework SourseHow do I differentiate these problems y x73 y 3x 2x2 23x2
How do I differentiate these problems:
y= x^7/3
y= (3/x) - (2/(x^2)) + (2/(3x^2))
f(x) = 1/4X^8 - 1/2X^6 - x + 2
f(u) = 0.07u^4 - 1.21u^3 + 3u - 5.2
y= x^7/3
y= (3/x) - (2/(x^2)) + (2/(3x^2))
f(x) = 1/4X^8 - 1/2X^6 - x + 2
f(u) = 0.07u^4 - 1.21u^3 + 3u - 5.2
Solution
use d/dx(x^n) = nx^(n-1) y= x^7/3 y\' = 7/3* x^(4/3) y= (3/x) - (2/(x^2)) + (2/(3x^2)) y\' = -3/x^2 + 4x^-3 -4/3x^-3 f(x) = 1/4X^8 - 1/2X^6 - x + 2 f\'(x) = -2x^-9 + 3x^-7 -1 f(u) = 0.07u^4 - 1.21u^3 + 3u - 5.2 f\'(u) = 0.28u^3 -3.63u^2 +3
