Cade throws a baseball from a starting height of 6 feet with

Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second Which of the following equations shows the path of the baseball? H(t)=-16t^2 + 6t + 22 H(t) =-16t^2 + 22t + 6 H(t) = -16t^2 + 28t H(t) = -16t^2 + 28

Solution

All the equations given are of 2nd degree and represent parabolas opening downwards. In the 2nd equation i.e. H(t) = -16t² +22t +6, the height is 6 when t = 0. Thus, the basketball has been thrown from a height of 6 feet. This is the only equation, where H(0) = 6 feet. Thus, the 2nd option, i.e. H(t) = -16t² +22t +6, is the correct answer.