can someone help me solve this problem seafch go book conten
Solution
a)
Calculating the standard deviation of the differences ,
s = 13.56075784
Thus, the standard error of the difference is sD = s/sqrt(n):
sD = 2.397225957
Calculating the mean of the differences (third column):
XD = 12.90625
For the 0.95 confidence level,
alpha/2 = (1 - confidence level)/2 = 0.025
t(alpha/2) = 2.039513446
lower bound = [X1 - X2] - t(alpha/2) * sD = 8.017075427
upper bound = [X1 - X2] + t(alpha/2) * sD = 17.79542457
Thus, the confidence interval is
( 8.017075427 , 17.79542457 ) [ANSWER]
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b)
YES, IT CONTRADICTS IT. The confidence interval is totally less than 20 points. [CONCLUSION]
